Nilai lim_(x→0)⁡ (-x^2)/(1-cos⁡ x)=⋯

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Bahas Soal Matematika   »   Limit   ›  

Nilai \( \displaystyle \lim_{x \to 0} \ \frac{-x^2}{1-\cos x} = \cdots \)

  1. -2
  2. -1
  3. 0
  4. 1
  5. 2

(SPMB 2005)

Pembahasan:

\begin{aligned} \lim_{x \to 0} \ \frac{-x^2}{1-\cos x} &= \lim_{x \to 0} \ \frac{-x^2}{2 \sin^2 \frac{1}{2} x} \\[8pt] &= -\frac{1}{2} \cdot \lim_{x \to 0} \ \frac{x}{\sin \frac{1}{2} x} \cdot \lim_{x \to 0} \ \frac{x}{\sin \frac{1}{2} x} \\[8pt] &= -\frac{1}{2} \cdot \frac{1}{\frac{1}{2}} \cdot \frac{1}{\frac{1}{2}} \\[8pt] &= -2 \end{aligned}

Jawaban A.